简单可靠的消息推送服务

  async function sendMessage() {
    const apiKey = 'your-api-key';
    const url = `https://www.notifyx.cn/api/v1/send/${apiKey}`;
    
    const response = await fetch(url, {
      method: 'POST',
      headers: {
        'Content-Type': 'application/json'
      },
      body: JSON.stringify({
        title: 'NotifyX',
        content: '世界上最好最快的消息平台',
        description: '免费消息推送服务'
      })
    });
    
    const result = await response.json();
    console.log(result);
  }